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1+1为什么等于2

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全扣分唷！！！！！！！
在此呃ｐｏｓｔ？！
[mib]:mad::mad:

[[i] Last edited by karywing on 2005-7-15 at 15:03 [/i]]

這不是學校討論,被人扣分好正常.

=3=....
唔應該啊~!

1+1並不是一定=2
example(+)1+(-)1=0

1+1=0, prove it!!

(I will prove it later in here if I remember this post)

[[i] Last edited by WTF on 2006-1-10 at 09:26 [/i]]

[quote]Originally posted by [i]戀櫻[/i] at 2006-1-9 18:38:
1+1並不是一定=2
example(+)1+(-)1=0 [/quote]

She is saying one plus one, not one plus minus one.

[quote]Originally posted by [i]WTF[/i] at 2006-1-10 09:25:


She is saying one plus one, not one plus minus one. [/quote]

咁佢係唔係1 + 1 先
仲有,呢D只小六時,阿sir話俾我地聽啫!

[quote]Originally posted by [i]WTF[/i] at 2006-1-10 09:03:
1+1=0, prove it!!

(I will prove it later in here if I remember this post)

[[i] Last edited by WTF on 2006-1-10 at 09:26 [/i]] [/quote]

十進數真係冇乜可能
equation solve 成 0 的可能性﹕
x-x=0   ->  -x+x=0
二進就易Ｄ
1.1 bit adder 加埋就出0
2.take 1's comp再加埋都係0

We all know 1+1=2, so here is the prove and see if you guys know what'w wrong of it [O-)].

Let a=b=1

By formula

(a^2-b^2)=(a+b)(a-b)

Both sides divided by (a-b) which becomes
                  (a^2-b^2)/(a-b)=(a+b)(a-b)/(a-b)
Therefore   (a^2-b^2)/(a-b)=(a+b)
Left hand side a^2-b^2 = 1x1-1x1=0
Right hand side a+b=1+1
by defination, 0/any number = 0
Therefore 0/(a-b)=0=1+1(Right hand side)
Hence 1+1=0 Proved!

We all know 1+1=2, so here is the prove and see if you guys know what'w wrong of it .

Let a=b=1

By formula

(a^2-b^2)=(a+b)(a-b)

Both sides divided by (a-b) which becomes
                  (a^2-b^2)/[color=Red](a-b) [/color]=(a+b)(a-b)/[color=Red](a-b)[/color]
Therefore   (a^2-b^2)/[color=Red](a-b)[/color]=(a+b)
Left hand side a^2-b^2 = 1x1-1x1=0
Right hand side a+b=1+1
by defination, 0/any number = 0  
Therefore 0/[color=Red](a-b)[/color]=0=1+1(Right hand side)
Hence 1+1=0 Proved!

---------------------------------------------------------------------------
紅色字個到一開始以經錯…
since a=b=1
0/(a-b) -> 0/(1-1) -> 0/0 -> infinite
∴1+1 not equal to 0
----------------------
provide一次比你睇
Let a=b=1
By formula
(a+b)(a+b)=a^2+2ab+b^2
(a+b)=(a^2+2ab+b^2)/(a+b)
sub 1 into a,b
left hand side
1+1
right hand side
[1^2+2(1)(1)+1^2]/(1+1)
=(1+2+1)/2
=2
∴1+1=2

[quote]Originally posted by [i]nicknick[/i] at 2006-1-10 20:50:

0/(a-b) -> 0/(1-1) -> 0/0 -> infinite[/quote]


Good for you. You know the concept quite well. I tried this on lots of ppl and most of them don't know why and where is the mistake. What grade are you in?

[[i] Last edited by WTF on 2006-1-11 at 05:46 [/i]]

問邊個都吾知la